the area of a circle is 154 cm². find the area of a square inscribed in the circle
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Answer:
mark brainliest plss
Step-by-step explanation:
Area of the circle = 154 sq cm
⇒\pi r^2 = 154
⇒ \frac{22}{7} r^2 = 154
⇒ r^2 = 49
⇒r = 7 cm
Let the side of the triangle = a cm
So, s = \frac{3a}{2}
But the radius of the incircle, r = \frac{\Delta}{s} Where Δ = Area of the triangle and s = semi-perimeter
7 = \frac{ \frac{ \sqrt{3} }{4} a^2 }{ \frac{3a}{2} }
7 = \frac{ \sqrt{3}a^2 }{2*3a}
7 = \frac{ \sqrt{3}a}{6}
a = \frac{42}{ \sqrt{3} }
a = \frac{42 \sqrt{3}}{3 } = 14 \sqrt{3}
Perimeter of triangle, 3a = 3*14 \sqrt{3} = 42 \sqrt{3}
Perimeter of triangle = 42(1.73) = 72.66 cm
Answered by
0
Answer:
the radius of the circle will be 7 cm.
so the side of the square will be 14 cm.
so the area of the square 14×14=196 cm×cm
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