Math, asked by harish6326, 9 months ago

The area of a circle is 25π sq.cm. Find

the length of its arc subtending an angle

of 144o

at the centre. Also find the area

of the corresponding sector.​

Answers

Answered by yogeshparashar452
6

Answer:

As we know that area of circle (A) is given by-

A=πr

2

Given that:-

Area of circle =25πcm

2

∴πr

2

=25π

⇒r=

25

=5cm

As we know that length of subtending arc (l) is-

l=rθ

where θ is the angle subtended by the arc

Given that tha angle subtended by the arc is 144°

θ=144°=144°×

180°

π

=

5

∴l=5×

5

=4πcm

As Area of sector =

2

1

×r×l

∴ Area of corresponding sector =

2

1

×5×4π=10πcm

2

Hence the length of subtending arc is 4πcm and the area of corresponding sector is 10πcm

2

.

please mark brqinlist

Answered by Anonymous
2

Answer:

<b><i><body bgcolor=66GFHJ><marquee direction="up"><font color=pink></b></i>

the area of a circle is 25π sq.cm.Find the length of its arc subtending an angle of 144° at the center. Also find the area of the corresponding sector

Answer:

given:- Area of circle = 55 pie sq.cm.

angle = 144°

144 \times \frac{\pi}{180} = \frac{4\pi}{5}

Step-by-step explanation:

we \: know \: that \: \\ \\ area \: of \: circle \: = \pi {r}^{2} \\ \\ 25\pi = \pi {r}^{2} \\ \\ {r }^{2} = 25 \\ r = 5cm \\ \\ lenth \: of \: arc \: = r \: × angle \\ 5 \times \frac{4\pi}{5} = 4\pi \: cm \\ \\ \\ area \: o \: sctor \: = \frac{1}{2} {r}^{2} agle \\ \frac{1}{2} ×5×5×\frac{4\pi}{5} \\ \\ = 10\pi \: \: sq \: cm

<body bgcolor=black><marquee direction="down"><font color=lime>

Follow meee

30thx+follow=inbox

Similar questions