Question

The area of a circle is 616 cm2.find it's circumference

Answer 1

Answer:

see the attached pic for answer

hope it will help you ..

if it helps mark brainliest

Answer 2

$\huge\bf\red{\underline{\underline{Given}}}\::$

• $\sf\orange{Area_{\:(circle)}\:=\:616cm^{2} }$

$\huge\bf\red{\underline{\underline{To\:Find}}}\::$

• $\sf\gray{ Circumference_{\:(circle)}}$

$\huge\bf\red{\underline{\underline{Solution}}}\::$

$\hookrightarrow\:\sf\pink{Area_{\:(circle)}\:=\:\pi r^{2}}$

$\hookrightarrow\:\sf\purple{616cm^{2} \: =\: \dfrac{21}{7}\:\times\:r^{2}}$

$\hookrightarrow\:\sf\pink{r^{2}\:=\:\dfrac{616\times 7}{22} cm</p><p>^{2}}$

$\hookrightarrow\:\sf\purple{r\:=\:\sqrt{\dfrac{616\times 7}{22} }cm}$

$\hookrightarrow\:\sf\pink{r\:=\:\sqrt{2\times7}\:cm}$

$\hookrightarrow\:\sf\purple{r\:=\:\sqrt{2\times7\times2\times7}\:cm}$

$\hookrightarrow\:\sf\pink{r\:=\:\sqrt{14\:\times\:14}\:cm}$

$\hookrightarrow\:\sf\purple{r\:=\:14cm}$

$\mapsto\:\sf\blue{Circumference_{\:(circle)}\:=\:2\pi r}$

$\mapsto\:\sf\orange{Circumference_{\:(circle)}\:=\:2\:\times\:\dfrac{22}{7}\:\times\:14}$

$\mapsto\:\sf\blue{Circumference_{\:(circle)}\:=\:2\:\times\:22\:\times\:2}$

$\mapsto\:\underline{\boxed{\sf{\orange{Circumference_{\:(circle)}\:=\:</p><p>88cm}}}}$

$\Large\bf\red{\underline{\underline{Additional\: Information}}}\::$

$\star\:\sf\underline\pink{Formula\:related\:to\:circle}$

• $\sf\red{Area_{\;(cricle)} = \pi r^2}$

• $\sf\orange{Area_{\;(Perimeter)} = 2 \pi r}$

• $\sf\green{Area_{\;(semicricle)} = \dfrac{ \pi r^2}{2}}$

• $\sf\blue{Perimeter_{\;(semi cricle)} = \pi r + 2r}$

• $\sf\purple{Area_{\;(quadrant)} = \dfrac{ \pi r^2}{4}}$

• $\sf\red{Area_{\;(sector)} = \dfrac{ \theta}{360^\circ} \times \pi r^2}$

• $\sf\orange{ Perimeter_{\;(sector)} = \dfrac{ \theta}{360^\circ} \times 2 \pi r + 2r}$

• $\sf\green{Area_{\;(segment)} = \dfrac{ \theta}{360^\circ} \pi r^2 - \dfrac{1}{2} r^2 sin \theta}$

• $\sf\blue{Perimeter_{\;(segment)} = \dfrac{\pi r \theta}{180^\circ} + 2r \dfrac{ \theta}{2}}$