the area of a circle is 9pir its circumference is???
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circumference __2pi r
area__πr(r)
9pir__πr(r)
pi pi cAncelled so remaining is 9__r(r)
r__3[square root of 9
so by putting value in circumference the answer comes
area__πr(r)
9pir__πr(r)
pi pi cAncelled so remaining is 9__r(r)
r__3[square root of 9
so by putting value in circumference the answer comes
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