The area of a circle is increased by 22 cm2 when its radius is increased by 1 cm. The originalradius of the circle is
(a) 6 cm
(b) 3 cm
(c) 4 cm
(d) 3.5 cm
Answers
Answered by
2
Step-by-step explanation:
Correct Answer:
C) 3 cm
Description for Correct answer:
Let original radius be r.
Then, according to the question,
\( \Large \pi (r+1)^{2}-\pi r^{2} \)=22
=> \( \Large \pi\times [(r+1)^{2}-r^{2}] \)=22
=> \( \Large \frac{22}{7}\times (r+1+r)(r+1-r) \)=22
=> 2r+1=7 => 2r=6
r=\( \Large \frac{6}{2} \)=3 cm
Answered by
0
3 cm
explanation
TLet the radius be 'r'
Radius increased by 1 cm so,
New radius be 'r+1'
So, as per question
⇒π(r+1)2−πr2=22
⇒π[(r+1)2−r2]=22
⇒722[r2+2r+1−r2]=22
⇒2r+1=7
⇒2r=6
⇒r=3 cm
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