Question

the area of a circle, whose radius is 16 centimetres is trisected by 2 concentric circles. the ratio of the radii of the concentric circles in ascending order is

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Let O be the center of a circle whose radius OA = 6 cm.

Its area = πr

2

=π(6)

2

=36πcm

2

Now, the area of this circle is trisected by two

concentric circles having radii OB and OC respectively.

∴ Area of the smallest circle ( with radius OC)

=

3

36π

cm

2

⇒π×OC

2

=12π⇒OC

2

=12

⇒OC=2

3

cm

solution