the area of a circle whose radius is the diagonal of a square whose area is 4 is
riteshpal2013:
please give me answer
6,8,16,4pai isme se ans. batana he
mera answer to 25.1 aaya hai
square area = 4
length of each side is 2
by pythagoras theorem....diagonal length is \sqrt{8}
radius = \sqrt{8}
area of circle = \pi r^{2}
25.132
length of each side is 2
by pythagoras theorem....diagonal length is \sqrt{8}
radius = \sqrt{8}
area of circle = \pi r^{2}
25.132
Answers
Answered by
1
hi there,
area of square =4
so by Pythagoras theorem the diagonal =√8=radius
area of the circle=πr^2=25.132
i hope this helps u...
area of square =4
so by Pythagoras theorem the diagonal =√8=radius
area of the circle=πr^2=25.132
i hope this helps u...
Answered by
2
the area of the square = 4
therefore length of each side is ,
area = side *side
4 = side *side
2*2 = side *side
therefore length of 1 side = 2
diagonal of a square = side * √2
= 2 √ 2
A.T.Q ,
diagonal of square = radius of the circle
area = πr²
area = 22/7 * 2√2 * 2√2
area = 22/7 * 2 * 2 * 2
area = 22/7 * 8
area = 25 .132
therefore the answer is 25.132
i hope that this will help u.....................^_^
therefore length of each side is ,
area = side *side
4 = side *side
2*2 = side *side
therefore length of 1 side = 2
diagonal of a square = side * √2
= 2 √ 2
A.T.Q ,
diagonal of square = radius of the circle
area = πr²
area = 22/7 * 2√2 * 2√2
area = 22/7 * 2 * 2 * 2
area = 22/7 * 8
area = 25 .132
therefore the answer is 25.132
i hope that this will help u.....................^_^
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