The area of a circle whose sides is a diameter of a circle of area 4s square pi
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Step-by-step explanation:
Given The area of a square whose sides is a diameter of a circle of area 4s square pi
We know that area of a circle = π r^2
Given area of a circle = 4s^2π
So π r^2 = 4s^2 π
Now r^2 = 4s^2
So r = 2s
Given diameter = 4s
So area of a square whose side is a diameter will be l^2 = 4s x 4s = 16 s^2
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