Question

the area of a circle with radius 13 cm is equal to the sum of area of circle with radius 3 cm 4 cm and X find x​

Answer 1

The area of circle C

The area of circle C 1

The area of circle C 1

The area of circle C 1 whose radius is 4 cm=π(4)

The area of circle C 1 whose radius is 4 cm=π(4) 2

The area of circle C 1 whose radius is 4 cm=π(4) 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cm

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3)

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2Let the radius of the new circle be R cm

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2Let the radius of the new circle be R cmArea of big circle =16π+9π=25π sq cm

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2Let the radius of the new circle be R cmArea of big circle =16π+9π=25π sq cm πR

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2Let the radius of the new circle be R cmArea of big circle =16π+9π=25π sq cm πR 2

The area of circle C 1 whose radius is 4 cm=π(4) 2 =16π sq cmAnd the area of circle C 2 whose radius is 3 cm=π(3) 2 =9π sq cm Given: Area of the new circle is equal to the sum of areas of circles C 1 and C 2Let the radius of the new circle be R cmArea of big circle =16π+9π=25π sq cm πR 2 =25π

R

R 2

R 2 =25

R 2 =25 R=5 cm

R 2 =25 R=5 cmSo the radius of the new circle =5 cm

Answer 2

Answer:

The area of circle C1 whose radius is 4 cm=π(4)2

                                                                          =16π sq cm

And the area of circle C2 whose radius is 3 cm=π(3)2

                                                                                  =9π sq cm 

Given: Area of the new circle is equal to the sum of areas of circles C1 and C2

Let the radius of the new circle be R cm

Area of big circle =16π+9π=25π sq cm 

⇒                 πR2=25π

⇒                    R2=25

⇒                     R=5 cm

So the radius of the new circle =5 cm