Question

the area of a circular cylinder is increased 6 times and the base area decreased one sixteenth of its value the factor by which the lateral surface of the cylinder increases is​

Answer 1

Step-by-step explanation:

Decrease in base radius

=(Decrease in base area)1/2=(19)12=13=(Decrease in base area)1/2=(19)12=13

Let initial radius and height be 3r and h

∴∴ New radius and height are r and 6 h

old lateral surface area =2×π×3r×h=6πrh=2×π×3r×h=6πrh

New lateral surface area

=2×π×3r×h=2×π×3r×h

=6πrh=6πrh

New lateral surface area

=2×πr×6h=12πrh=2×πr×6h=12πrh

Required factor =12πrh6πrh=2

Answer 2

Step-by-step explanation:

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