The area of a circular field is 154 m2. Find the time taken by an athlate to complete
2 rounds if she is jogging at the rate of 5 km/hr.
Answers
Answered by
32
22/*r*r=154
r*r=49
r=7
therefore, perimeter=2*22/7*7=44
the distance traveled by her=2*44=88=.088km
we know that- speed =distance/time;
5=.088/t
then, t=0.88/5=0.176.hr.
r*r=49
r=7
therefore, perimeter=2*22/7*7=44
the distance traveled by her=2*44=88=.088km
we know that- speed =distance/time;
5=.088/t
then, t=0.88/5=0.176.hr.
Answered by
31
area of circle = [tex] \pi r^2
[/tex]
154 = [tex] \frac{22}{7} * r^2 [/tex]
= r
r = 7 m
circumference =
=
= 88m
time = ditance / speed
=
=
154 = [tex] \frac{22}{7} * r^2 [/tex]
r = 7 m
circumference =
=
= 88m
time = ditance / speed
=
=
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