Question

The area of a circular
garden is 5544 m sq. Outside
this garden, a path of
mitorm width is laid all
around. The area of the
path is 2002 m sq. find
i) The radius of the circular
garden
ii) the width of the path.​

Answer 1

Answer:

$1.r = 42 m\\ 2.path = 7m$

Step-by-step explanation:

$area \: of \: circular \: garden = 5544sq.m \\ \pi \: {r}^{2} = 5544 \\ {r}^{2} = \frac{5544 \times 7}{4 \times 22} \\ r = 42 \\ area \: of \: garden \: + area \: of \: path = 5544 + 2002 = 7546 \\ \pi capital \: {r}^{2} = 7546 \\ capital \: {r}^{2} = \frac{7546 \times 7}{22} = 343 \times 7 = 2401 \\ capital \: r = 49 \\ width \: of \: the \: path = 49 - 42 = 7m$