Question

The area of ​​a circular garden is 554400 sq. M. Is. So what is the circumference of that garden?

pls solve step by step ​

Answer 1

area of circle =

$\pi {r}^{2}$

$\frac{22}{7} \times {r}^{2} = 554400 \\ {r }^{2} = 554400 \times \frac{7}{22} \\ {r }^{2} = 25200 \times 7 \\ r = \sqrt{25200 \times 7} \\ r = \sqrt{25 2 \times 100 \times 7 } \\ r = \sqrt{1764 \times 100} \\ r = \sqrt{ {42}^{2} \times {10}^{2} } \\ r = 42 \times 10 \\ r = 420m \\ circumefrance \: \\ 2\pi \times r \\ 2 \times \frac{22}{7} \times 420 \\ 2 \times 22 \times 60 \\ 44 \times 60 \\ 2640answer$

Answer 2

Answer:-

Circumference of the garden will be 2640m.

Step by step Solution:-

Given-:

Area of the circular garden = 554400 m²

As area of circle = πr²

Therefore According To Question:-

$= > \pi {r}^{2} = 554400 \\ = > \frac{22}{7} \times {r}^{2} = 55400 \\ = > {r}^{2} = \frac{554400 \times 7}{22} \\ = > {r}^{2} = \frac{ \cancel554400 \times 7}{ \cancel22} \\ = > {r}^{2} = 25200 \times 7 \\ = > r = \sqrt{176400} \\ = > \boxed{\large \bold {r = 420}}$

Now,

Circumference of circle = 2πr

As radius is 420 m so,

Circumference of circular garden = 2πr

$= > 2 \times \frac{22}{7} \times 420 \\ = > 2 \times \frac{22}{ \cancel7} \times \cancel420 \\ = > 2 \times 22 \times 60 \\ = > 2640$

Hence:-

The circumference of the garden will be 2640m.