Question

The area of a circular path is 31,416 m' and the radius of the inner circular boundary is 350 m. Find the radius of the outer boundary​

Answer 1

Answer:

4998

Step-by-step explanation:

Area(circumference) =31416m

C=2πr

31416=2×22/7×r

44r = 219912

r = 219912÷44

r = 4998

.°. r= 4998

Answer 2

The radius of outer boundary is 364 m

Step-by-step explanation:

Let the outer radius(R) be x

Inner radius (r)= 350 m

Area of path = Outer area - inner area

We are given that The area of a circular path is 31,416 sq.m.

So,$31416 = \pi R^2 - \pi r^2\\31416=\frac{22}{7}(x^2-350^2)\\\frac{31416 \times 7}{22}=(x^2-350^2)\\9996+350^2=x^2\\\sqrt{9996+350^2}=x\\364 = x$

Hence The radius of outer boundary is 364 m

#learn more:

A circular path runs around a circular flower bed if the circumference of the flower bed and path are 88 m and 132 m respectively, find the width of the path also find the area of path

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