Question

The area of a circular region is 308 square CM the perimeter of the square inscribed in that circle is

Answer 1

Answer:

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$so \: here \: area \: of \: circular \: region=308 cm.square </p><p> \\ so \: we \: know \: that \\ area \: of \: circular \: region = area \: of \: circle = \pi.rsquare$

$so \: thus \: then \\ 308 = \pi.r \: square \\ ie \: 308 = 22 \div 7.r \: square \\ ie \: 14 = r.square \div 7 \\ ie \: r.squar = 98 \\ taking \: square \: roots \: on \: both \: sides \\ \\ we \: get \\ r = 7 \sqrt{2} cm$

$thus \: diameter = 2 \times 7 \sqrt{2} = 14 \sqrt{2} \: cm \\ so \: here \: diameter \: of \: circle \: is \: diagonal \: of \: inscribed \: square \\ \\ so \: we \: know \: that \: diagonal \: of \: square = \sqrt{2}.side \: of \: square \\ ie \: 14 \sqrt{2} = \sqrt{2}.side \: of \: square \\ \\ ie \: side \: of \: square = 14 \: cm$

$now \: we \: know \: that \\ perimeter \: of \: square = 4.side \: of \: square \\ = 4 \times 14 \\ = 56 \: cm \\ \\ hence \: perimter \: of \: square \: is \: 56 \: cm$