Question

the area of a circular track whose outer and inner radius is 5 cm and 4 cm is​

Answer 1

Step-by-step explanation:

$\bf \huge \text{ \purple{\underline{Question}}}$

• the area of a circular track whose outer and inner radius is 5 cm and 4 cm is

___________________________

$\bf \huge \text{ \purple{\underline{</strong><strong>given</strong><strong>}}}$

• outer and inner radius is 5 cm and 4 cm .

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$\bf \huge \text{ \purple{\underline{</strong><strong>To</strong><strong> </strong><strong>Find</strong><strong>}}}$

• The area of a circular track ?.

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$\bf \huge \text{ \purple{\underline{Solution}}}$

$\sf \purple{ \to\pi( {5}^{2} - {4}^{2} )}$

$\bf \text{ \purple{\underline{on adding}}}$

$\sf \purple{ \to \: \pi(5 - 4)(5 + 4)}$

$\bf \text{ \purple{\underline{on substraction}}}$

$\sf \purple{ \to \: \pi(9)}$

There fore the answer is

$\sf \purple{ \to \: 9\pi}$

Answer 2

first area of outer circle =^R square

=22/7×5×5

=78.53

then area of inner circle =^r square

=22/7×4×4

=50.26

area of track =78.53-50.26

=28.27