Question

the area of a equlateral triangle is 8√3 cm square .What is the height of a
triangle?​

Answer 1

Step-by-step explanation:

$= > area = 8 \sqrt{3} \\ \\ = > \frac{ \sqrt{3} }{4} {x}^{2} = 8 \sqrt{3} \\ \\ = > {x}^{2} = 32 \\ \\ = > x = \sqrt{32} \: cm \\ \\ we \: know \\ \\ area = \frac{1}{2} \times base \times height \\ \\ = > height = \frac{2 \times 8 \sqrt{3} }{ \sqrt{32} } \\ \\ = > height = 16 \sqrt{3} \times \frac{1}{4 \sqrt{2} } \\ \\ = > height = \frac{4 \sqrt{3} }{ \sqrt{2} } \\ \\ = > height = 2 \sqrt{6} cm$