the area of a isosceles ∆ having base 2cm & the length of the one of ∆ equal side 4cm then find the area of ∆
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√15
By herons formula
side a =2 cm
side b= 4 cm
side c =4 cm
s= half of perimeter=5
√s(s-a)(s-b)(s-c)
√5(5-2)(5-4)(5-4)
√5×3×1×1
√5×3
√15
By herons formula
side a =2 cm
side b= 4 cm
side c =4 cm
s= half of perimeter=5
√s(s-a)(s-b)(s-c)
√5(5-2)(5-4)(5-4)
√5×3×1×1
√5×3
√15
sunil175:
thanks pa
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