Question

the area of a parallelogram ABCD in which ab is 7.5 cm and perpendicular from C to ab is 7 cm​

Answer 1

Answer:

Consider Δ ABC

It is given that AB = 7.5cm, BC = 7cm and AC = 6.5cm

Take a = 7.5cm, b = 7cm and c = 6.5 cm

So we get

s=  a+b+c    /    2

​s=  7.5+7+6.5     /   2

By division

s=10.5cm

We know that

Area=  

s(s−a)(s−b)(s−c)

​  

 

By substituting the values

Area=  √10.5(10.5−7.5)(10.5−7)(10.5−6.5)

​  

So we get

Area=  10.5×3×3.5×4

​  

It can be written as  

Area=  root 441

​  

 

By multiplication

Area=21cm^2

 We know that the area of parallelogram DBCE = Area of Δ ABC

It can be written as

BC×DL=21

By substituting the values

7×DL=21

By division

DL = 3cm

Therefore, the height DL of the parallelogra m

hope it helps

tq./

Step-by-step explanation: