Question

The area of a parallelogram is 26 sq cm. If its base is 6.5 cm, what is its height

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\sf\underline{\pink{\:\:\:\:\:\:\:Given:-\:\:\:\:\:\:\:}}$

$\sf\bullet Area\:of\: parallelogram=26cm{}^{2}\\ \\ \sf\bullet Base=6.5cm\\ \\ \sf\bullet Height= ?$

Now

$\bf\underline{\red{\:\:\:\:\:\:\:A.T.Q:-\:\:\:\:\:\:\:}}$

$\boxed{\sf{Area\:of\: parallelogram=Base\times Height}}$

$\sf:\:\:\: Put\:the\:\: Values\\ \\ \sf:\implies 26=6.5\times height\\ \\ \sf:\implies \cancel{\dfrac{26}{6.5}}=Height\\ \\ \sf:\implies 4cm=Height$

$\boxed{\bf{Height\:of\: parallelogram=4cm}}$

Answer 2

Answer:

• Height of parallelogram = 4 cm

Step-by-step explanation:

Given :

• Area of parallelogram = 26 cm²

• Base of parallelogram = 6.5 cm

To find :

• Height of parallelogram = ?

According to the question :

Area of parallelogram = Base × Height

26 = 6.5 x height

Height = 26/6.5

Height = 4 cm

Thus, the height of the parallelogram = 4 cm.