Question

The area of a parallelogram is 338 square metre if its altitude is twice the corresponding base determine the base and the altitude

Answer 1

Let the base be x

then,

altitude=2x

area of parallelogram=base×altitude

338 m²=2x×x

2x²=338 m²

x²=169 m²

x=13 m

therefore,

base=13 m

and altitude=26 m

Answer 2

Given-

• Area of a parallelogram is 338 metre².
• Its attitude is twice the corresponding base.

To find:-

• Find the base and altitude of the Parallelogram ?

Solutions:-

• Let the base of the Parallelogram be 'b' m.
• Let the height of the Parallelogram be 'h' m.

If its attitude is twice the corresponding base.

=> h = 2b .......(i).

We know that,

The area of parallelogram = base × height

Putting the value of h from equation (i).

=> 338 = b × h

=> 338 = b × 2b

=> 338 = 2b²

=> 338/2 = b²

=> 169 = b²

=> √169 = b

=> 13 = b

=> b = 13m

Put the value of 'b' in equation (i).

=> h = 2b

=> h = 2 × 13

=> h = 26m

Hence, the height of the Parallelogram is 26 m and base of parallelogram is 13m.

Some Important:-

• Area of parallelogram = base × height
• perimeter = 2 (l + b)

where,

• l = length
• b = breadth
• a = area
• p = perimeter