Question

The area of a parallelogram is 338m2. If its altitudes is twice the corresponding base find the base and the altitudes.​

Answer 1

Given :

Area of parallelogram = 338m^2

Altitude(h)=2*base (b)

We Know,

Area of parallelogram= base* height

substituting values,

Area of Parallelogram =

b*2b = 338m^2

or, 2 b^2 = 338

Or, b^2 = 169

Or, b = 13 m [Note: side of parallelogram can't be negative]

Therefore, altitude = 2b = 26m

Answer 2

Step-by-step explanation:

let the base be =x

altitude=2x

area=338m^2

area of the trapezium= 1/2×(sum of parallel side) ×altitude

338 =1/2 × (x+x) × 2x

338=1/2×4x^2

4x^2=338×2/1

x^2=676/4

x =√169

x=13

height = 26