Question

The area of a parallelogram is 392 m2

.If its altitude is twice the corresponding base,

determine the base and height.​

Answer 1

Answer:

Let the base(b) be 'x'

Given altitude is twice the base

It means,altitude(h) = 2x

Area of a parallelogram = bh

Given area of the parallelogram = 392 m²

⇒(bh)=392m²

⇒(x)(2x)=392m²

⇒2x²=392m²

⇒x²=392m²/2

⇒x²=196m²

⇒x=√196m²

⇒x=14m.

Therefore,the base of the parallelogram(x)=14m and

                 the altitude of the parallelogram(2x)=2(14)=28m

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Answer 2

Answer:

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Step-by-step explanation:

so let the altitude of parallelogram be h m and its base be b m

so here according to the given condition

h=2b (1)

we know that

area of parallelogram=height×base

so here area=392 m.square

thus then

392=hb

=2b×b

ie b square =196

taking square roots on both sides

we get

b=14 m or b=-14m

but as dimensions length are never negative b=-14 is absurd

thus b=14 m

substituting value of b in (1)

we get h=28 m

hence base of given parallelogram is 14 m and its height is 28 m