Math, asked by hoodaketan356, 1 month ago

The area of a parallelogram is 392 m2

.If its altitude is twice the corresponding base,

determine the base and height. please tell in a perfect solution​

Answers

Answered by VishalSharma01
54

Answer:

Step-by-step explanation:

Given,

  • The area of a parallelogram is 392 m² .
  • Altitude is twice the corresponding base.

To Find,

  • Base and Height.

Formula to be used,

  • Area of a parallelogram = Base × Height

Solution,

Let the base be x.

Then, height = 2x

According to the Question,

Base × Height = 392 m²

⇒ x × 2x = 392 m²

⇒ 2x² = 392 m²

⇒ x² = (392 m²)/2

⇒ x² = 196 m²

⇒ x = √196 m²

x = 14 m

Hence, the base of the parallelogram is 14 m.

And, Height = 2x = 2 × 14 = 28 m.

Hence, the height of the parallelogram is 28 m.

Answered by MяMαgıcıαη
111

G I V E N

  • The area of parallelogram (llgm) is 392 .

  • It's altitude is twice the corresponding base.

T OF I N D

  • Base and height of llgm ?

S O L U T I O N

  • Let the base of llgm be a

  • So, it's height is 2a (Because it is given that altitude is twice the given base).

Using formula ::

\odot\:\underline{\boxed{\sf{Area_{(parallelogram)} = Base\:\times\:Height}}}

Putting all known values ::

➝ ㅤ392 = a × 2a

➝ ㅤ2a² = 392

➝ㅤ a² = 392/2

After cancelling 392 with 2, we get ::

➝ㅤ a² = 196

➝ㅤ a = √196

➝ㅤ a = 14

Finding base and height of parallelogram ::

  • Base = a = 14 m

  • Height = 2a = 2 × 14 = 28 m

Hence, base and height of llgm = 14 m and 28 m.

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