the area of a parallelogram is 392m^2.if its altitude is twice the corresponding base,determine the base and height .
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Area of the parallelogram = 392 m^2
Let the base of the parallelogram be b m.
Given:
The height of the parallelogram is twice the base.
Therefore, Height = 2b m
Area of a parallelogram = Base * Height
392 = b * 2b
392 = 2b^2
392\2=b^2
196 = b^2
b = 14
Therefore, Base = 14 m and Altitude = 2 * Base = 2 * 14 = 28 m
Let the base of the parallelogram be b m.
Given:
The height of the parallelogram is twice the base.
Therefore, Height = 2b m
Area of a parallelogram = Base * Height
392 = b * 2b
392 = 2b^2
392\2=b^2
196 = b^2
b = 14
Therefore, Base = 14 m and Altitude = 2 * Base = 2 * 14 = 28 m
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