Question

The area of a parallelogram is
45 square cm and length of its
bottom side is 9 cm. What is
the distance to its opposite
side? *​

Answer 1

Answer:

Findtheperimeterofarectanglebreath

=20cmlength=40cm

D I A G R A M :

\begin{gathered}\begin{gathered} \pink{\begin{gathered} \sf{20 \:m}\huge\boxed{ \begin{array}{cc} \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \ \: \: \end{array}} \\ \: \: \: \: \: \sf{40 \: m} \end{gathered}}\end{gathered}\end{gathered}

20m

40m

\large \sf \green{Given:-}Given:−

Length of Rectangle = 40 cm

Breadth of Rectangle = 20 cm

\sf \color{skyblue} \mapsto2(40 + 20) \: cm↦2(40+20)cm

\color{skyblue}{\bigstar \large\underline{\boxed{\bf\pink{Solution:-}}}}★

Solution:−

Formula :-

\dag \orange{ \boxed{\sf {Perimeter_{(Rectangle)} = 2( \ell + b)}}}†

Perimeter

(Rectangle)

=2(ℓ+b)

\frak \purple{ \underline{ \bigstar{Finding \: the \: perimeter \: of \: rectangle}}}

★Findingtheperimeterofrectangle

\sf \blue{= 2( \ell + b)}=2(ℓ+b)

\sf \color{skyblue}{ \mapsto 2( 40 + 20)}↦2(40+20)

\sf \color{gold} \mapsto2(60)↦2(60)

\sf \green{2 \times 60 = 120 \: cm}2×60=120cm

\pink{ \underline{ \boxed{ \bf{ \therefore \: The \: perimeter \: of \: rectangle = 120 \: cm}}}}

∴Theperimeterofrectangle=120cm