The area of a parallelogram is 72 cm2. If the base of the parallelogram is twice its altitude, then find its dimensions. ...ANSWER PLEASE....
Answers
☞︎︎︎ Question :
★ The area of a parallelogram is 72 cm²
★ base of the parallelogram is twice its altitude
★ find its dimensions.
☞︎︎︎ Given :
✞︎ Area = 72cm²
✞︎ base = 2× altitude
☞︎︎︎ To Find :
❥︎ Dimensions
☆ Let the altitude be = x
☞︎︎︎ Solution :
☕︎ Altitude = x
➪ Base = 2 × x = 2x
༒︎ On Transposing the terms :
☞︎︎︎ Altitude = x = 6cm
☞︎︎︎ Base = 2x = 2 × 6 = 12 cm
✰ Information :
☞︎︎︎ Let the values be = x and 2x
☞︎︎︎ use formula of area
☞︎︎︎ square when transposed will become square root
☞︎︎︎ Therefore, we get the answer
Step-by-step explanation:
☞︎︎︎ Question :
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ★ The area of a parallelogram is 72 cm²
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ★ base of the parallelogram is twice its altitude
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ★ find its dimensions.
☞︎︎︎ Given :
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ✞︎ Area = 72cm²
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ✞︎ base = 2× altitude
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ To Find :
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ❥︎ Dimensions
\: \: \: \: \: \: \: \: \: \:
☆ Let the altitude be = x
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ Solution :
\: \: \: \: \: \: \: \: \: \:
☕︎ Altitude = x
\: \: \: \: \: \: \: \: \: \:
➪ Base = 2 × x = 2x
\: \: \: \: \: \: \: \: \: \:
\looparrowright{ \boxed{ \boxed{ \mathtt{area = base \times height}}}}↬
area=base×height
\: \: \: \: \: \: \: \: \: \:
\implies \mathtt{72 = 2x \times x}⟹72=2x×x
\: \: \: \: \: \: \: \: \: \:
\implies \mathtt{ 72 = 2 {x}^{2} }⟹72=2x
2
\: \: \: \: \: \: \: \: \: \:
\: \: \: \: \: \: \: \: \: \: ༒︎ On Transposing the terms :
\: \: \: \: \: \: \: \: \: \:
\implies \mathtt{ \dfrac{72}{2} = {x}^{2} }⟹
2
72
=x
2
\: \: \: \: \: \: \: \: \: \:
\implies \mathtt{36 = {x}^{2} }⟹36=x
2
\: \: \: \: \: \: \: \: \: \:
\implies \mathtt{x = \sqrt{36} }⟹x=
36
\: \: \: \: \: \: \: \: \: \:
\large \dashrightarrow \boxed{ \mathtt{x = 6}}⇢
x=6
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ Altitude = x = 6cm
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ Base = 2x = 2 × 6 = 12 cm
\: \: \: \: \: \: \: \: \: \:
✰ Information :
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ Let the values be = x and 2x
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ use formula of area
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ square when transposed will become square root
\: \: \: \: \: \: \: \: \: \:
☞︎︎︎ Therefore, we get the answer