Math, asked by dogcat21, 7 months ago

The area of a parallelogram is 72 cm2. If the base of the parallelogram is twice its altitude, then find its dimensions. PLZ ANSWER!!!!

Answers

Answered by TejeswiniSure
2

Step-by-step explanation:

Area = 72cm

Let altitude be x

then base = 2x

Area = b*h

72 = 2x * x

72 = 2x^2

x^2 = 72/2

x^2 = 36

x = √36

x = 6

Altitude= 6

Base= 6*2= 12

Answered by Mounikamaddula
30

Answer:

Answer:

  • Base of a parallelogram=12cm
  • Altitude of a parallelogram=6cm

Given:

  • The area of a parallelogram=72sq.cm
  • And base of a parallelogram is twice its altitude.

To find:

  • The dimensions of a parallelogram.

Solution:

Since,

Base of a parallelogram(b) is twice its altitude(h).

b=2h

Area of the parallelogram=h

b \times h = 72

2h \times h = 72

2 {h}^{2}  = 72

 {h}^{2}   = 36

h = 6

So, The altitude of a parallelogram,h=6cm

base \: of \: a \: parallelogram = 2h = 12cm

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