Math, asked by minubasak0, 1 month ago

The area of a parallelogram is 98 cm². If one altitude is half the corresponding base, then<br />determine the base and the altitude of the parallelogram.<br />​

Answers

Answered by chaharsomya6
3

Answer:

TheQuestion:

The area of parallelogram is 98 cm square. If one of the altitude is half of the corresponding base, determine the base and altitude of the parallelogram.

\underline{\mathfrak{\huge{Your\:Answer:}}}

YourAnswer:

\sf{Given\:is\:that:}Givenisthat:

Area of the parallelogram = 98 sq. cm

If we let the base to be equal to b, and the corresponding height to be equal to h, it's given that :-

\begin{gathered}\tt{h = \frac{b}{2}}\\\end{gathered}

h=

2

b

Now, we know that, the area of any parallelogram is :-

Area of a parallelogram = Base × Height = b × h

Put the values in the formula, and then, simply solve it, you will get your answer :-

=》 \tt{98 = b \times h}98=b×h

Put the value of h, we obtained from the above discussion:-

=》 \begin{gathered}\tt{98 = b \times \frac{b}{2}}\\\end{gathered}

98=b×

2

b

Take 2 on the L.H.S. and then solve it:-

=》 \tt{98\times 2 = b^{2}}98×2=b

2

Multiply 196 by 2 and then find the value of b :-

=》 \tt{196 = b^{2}}196=b

2

Do square root and then find the value of b :-

=》 \tt{b = \sqrt{196}}b=

196

The value of b is:-

=》 \tt{b = 14 cm}b=14cm

Thus, the base is = 14 cm

Height of the parallelogram = \begin{gathered}\tt{\frac{b}{2}}\\\end{gathered}

2

b

Height = \begin{gathered}\tt{\frac{14}{2}}\\\end{gathered}

2

14

Height of the parallelogram = \tt{7 cm}7cm

We found that :-

Base = 14 cm

Height = 7 cm

Answered by darkthunder1234567
0

area = base into height

base = 2 height

98 = 2 into x into x

98 divided by 2 = x square

49 = x square

7 = x

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