Question

The area of a parallelogram is y cm2 and its height is h cm. The base of another parallelogram is x cm more than the base of the first parallelogram and its area is twice the area of the first. Find, in terms of y, h and x, the expression for the height of the second parallelogram.​

Answer 1

Here is your answer ...............

Answer 2

$\sf{\huge{\underline{\red{Given :-}}}}$

• The area of a parallelogram is y cm² and its height is h cm.

• The base of another parallelogram is x cm more than the base of the first parallelogram and its area is twice the area of the first.

$\sf{\huge{\underline{\pink{To\:Find :-}}}}$

• The expression for the height of the second parallelogram.

$\sf{\huge{\underline{\green{Solution :-}}}}$

Let the base of parallelogram be y cm.

And, the area of parallelogram be a cm.

We get,

The Height of first parallelogram be :-

h = $\dfrac{y}{a}$

So, the height of the second parallelogram be h'.

The area of parallelogram 2 = 2y

Base of the parallelogram = ( a + x )

2y = ( a + x ) h'

➝ 2y = ( $\dfrac{y}{h}$ + x ) h'

➝ y = $\dfrac{2yh}{y+hx}$

So, We get the The expression for the height of the second parallelogram ➝

$\dfrac{2yh}{y+hx}$

________________________________