the area of a quadrant is 154cm². find the perimeter.
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- given area =154cm^2
- given area =154cm^2πr^2=154
- given area =154cm^2πr^2=154r^2=154/π
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49r=7
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49r=7perimeter of circle =circumfrance
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49r=7perimeter of circle =circumfrance=2πr
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49r=7perimeter of circle =circumfrance=2πr=2 *22/7 *7
- given area =154cm^2πr^2=154r^2=154/πr^2=154/22/7r^2=(154*7)/22r^2=49r=7perimeter of circle =circumfrance=2πr=2 *22/7 *7=44cm
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