Question

the area of a rectabngular park is 1560cm2 and its breadth is 24m. find the length and perimeter of the park .Also find the cost of fencing it at ₹22.50 per metre .

Answer 1

Let length of park be l
breadth of park = 24m
area of rectangle = l×b
l×b =1560
24×l =1560
l =65 m
perimeter of park =2(l+b)
2(24+65)=2×89=178m
cost of fending will be = 178×22.50=4005 Rs

Answer 2

Hi there !

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Given :

Length of rectangular park = 24m

Area of rectangular park = 1560 m².

Solution :

Let the length of the rectangular Park be x cm.

We know that ;

Area of rectangle = length × breadth

⇒ 1560 = 24 × x

⇒ 24x = 1560

⇒ x = 1560 / 24

⇒ x = 65 m.

Length of the rectangular park = 65m.

Now,

Perimeter of rectangle = 2 ( l + b )

⇒ 2 ( 65 + 24 )

⇒ 2 × 89

⇒ 178 m

Now,

Cost of fencing it at ₹22.50 per metre .

⇒ ₹ ( 22.50 × 178 )

⇒ ₹ 4005

Hence, the cost of fencing is ₹ 4005.

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Thanks for the question !

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