Question

The area of a rectangle ABCD is 50 sq. cm. What will be
PCD (in sq. cm) formed by taking a point P on AB ?
triangle
6am and the altitude corresponding​

Answer 1

Area of the remaining part of sheet = Area of ABCD - Area of a semi-circle

= 20×14−

2

1

×

7

22

×

2

14

×

2

14

=280−77=203 cm

2

Answer 2

$\huge \fbox{ \: ANSWER \: }$

Let, Breadth of rectangle be x m.

And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]

We know,

Perimeter of rectangle = 2(Length + breadth)

Put the values :

⟶ 74= 2×(3x + 5 + x)

⟶ 74 = 6x + 10 + 2x

⟶ 74 = 8x + 10

⟶ 74 - 10 = 8x

⟶ 64 = 8x

⟶ 64/8 = x

⟶ x = 8

Let, Breadth of rectangle be x m.

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :⟶ 74= 2×(3x + 5 + x)

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :⟶ 74= 2×(3x + 5 + x)⟶ 74 = 6x + 10 + 2x

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :⟶ 74= 2×(3x + 5 + x)⟶ 74 = 6x + 10 + 2x⟶ 74 = 8x + 10

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :⟶ 74= 2×(3x + 5 + x)⟶ 74 = 6x + 10 + 2x⟶ 74 = 8x + 10⟶ 74 - 10 = 8x

Let, Breadth of rectangle be x m.And, Length of rectangle be 3x + 5 m. [We take length be 3x + 5 m because it is given that length is five meter more than thrice the Breadth.]We know,Perimeter of rectangle = 2(Length + breadth)Put the values :⟶ 74= 2×(3x + 5 + x)⟶ 74 = 6x + 10 + 2x⟶ 74 = 8x + 10⟶ 74 - 10 = 8x⟶ 64 = 8x

⟶ 64/8 = x

⟶ 64/8 = x⟶ x = 8

Verification:-

⟶ 74 = 2× (3x + 5 + x)

⟶ 74 = 2× (3x + 5 + x)Put x = 8

⟶ 74 = 2×(3×8 + 5 + 8)

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74 Now,

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74 Now,We take,

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74 Now,We take,Breadth be x. So, Breadth of rectangle is 8 m.

⟶ 74 = 2×(3×8 + 5 + 8)⟶ 74 = 2×(24 + 5 + 8)⟶ 74 = 2×(29 + 8)⟶ 74 = 58 + 16⟶ 74 = 74 Now,We take,Breadth be x. So, Breadth of rectangle is 8 m.Length be 3x + 5 = 3×8 + 5 = 29. Thus, Length of rectangle is 29 m.:-

⟶ 74 = 2× (3x + 5 + x)

Put x = 8

⟶ 74 = 2×(3×8 + 5 + 8)

⟶ 74 = 2×(24 + 5 + 8)

⟶ 74 = 2×(29 + 8)

⟶ 74 = 58 + 16

⟶ 74 = 74

Now,

We take,

Breadth be x. So, Breadth of rectangle is 8 m.

Length be 3x + 5 = 3×8 + 5 = 29. Thus, Length of rectangle is 29 m.