Question

The area of a rectangle field is 5184m^2. find the area of a rectangular field, whose perimeter is equal to the perimeter of the square field and whose length is twice of its breadth

Answer 1

I think Your Question Is :-

the area of square field is 5184m^2 . Find the area of a rectangular field, whose perimeter is equal to the perimeter of the perimeter of square field and whose length is twice of its breadth 

Solution :-

Area of square = Side^2

5184 =  side^2

$\sqrt{5184} = Side$

72m = Side of square 

Now,

Perimeter of square = 4*side

Perimeter of square = 4*72 m 

Perimeter of square = 288 m 
_______________________________

Now,

Let the breadth of rectangle be x,  and then the length be 2x

Then 

As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2*48) = 96m 

Now,

Area of rectangle = length * breadth

Here,

Area of rectangle =  48*96 

Area of rectangle =4608 m^2

i hope this will help you

-by ABHAY

Answer 2

Here is your solution

Given :-

Area of square = 6889 m^2

we have to find perimeter of square =?

Now

Area of square = side^2

=>5184 m^2 = side^2

=>72m =side of square

Now

perimeter of square => 4× side .
=> 4×72=288m

Now,

Let,
The breadth of rectangle be x

Then the length be 2x


As we know that,

 perimeter of a rectangle =2(length+breadth)

And, perimeter of square = perimeter of rectangle = 288m 

288 = 2(x + 2x)

288/2 = 3x

144 = 3x

144/3 =x

48 = x

Then,

breadth of rectangle = x = 48 m 

and length of rectangle = 2x = (2×48) = 96m 

Now,

Area of rectangle = length×breadth

Here,

Area of rectangle =  48×96 

Area of rectangle =4608 m^2

Hopeit helps you