Math, asked by abhinav7126, 9 months ago

The area of a rectangle gets reduced by 9 square units, if its length is reduced by
5 units and breadth is increased by 3 units. If we increase the length by 3 units and
the breadth by 2 units, the area increases by 67 square units. Find the dimensions
of the rectangle.​

Answers

Answered by Dɪʏᴀ4Rᴀᴋʜɪ
14

\huge\sf\red{Solution}

☯ Let's consider length and breadth of a rectangle be x and y units respectively.

Then,

Area of Rectangle = xy sq. units

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Now,

According to the Question:

Thee area of rectangle gets reduced by 9 square units If its length is reduced by 5 units and breadth by is increased by 3 units.

{\bold{\sf\green{➯ xy - 9 = (x - 5)(y + 3)}}}

{\bold{\sf\green{➯ xy - 9 = xy + 3x - 5y - 15}}}

{\bold{\sf\green{➯ - 9 = 3x - 5y - 15}}}

{\bold{\sf\green{➯ 3x - 5y = - 9 + 15}}}

{\bold{\sf\green{➯ 3x - 5y = 6}}}

{\bold{\sf\green{➯ - 5y = 6 - 3x}}}

{\bold{\sf\green{➯ y = - (6 - 3x)/5}}}

{\bold{\sf\green{➯ y = (3x - 6)/5}}} ⠀⠀⠀⠀⠀⠀⠀⠀❬ eq(1) ❭

And,

If we increase the length by 3 units and breadth by 2 units, the area increases by 67 square units.

{\bold{\sf\blue{➯ (x + 3)(y + 2)=xy + 67}}}

{\bold{\sf\blue{➯ xy + 2x + 3y + 6 = xy + 67}}}

{\bold{\sf\blue{➯ 2x + 3y + 6 = 67}}}

{\bold{\sf\blue{➯ 2x + 3y = 67 - 6}}}

{\bold{\sf\blue{➯ 2x + 3y = 61}}} ⠀⠀⠀⠀⠀⠀⠀⠀❬ eq(2) ❭

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Now, Putting eq (1) in eq (2),

{\bold{\sf\pink{➯ 2x + 3{(3x - 6)/5} = 61}}}

{\bold{\sf\pink{➯ 2x + (9x - 18)/5 = 61}}}

{\bold{\sf\pink{➯ (10x + 9x - 18)/5 = 61}}}

{\bold{\sf\pink{➯ 10x + 9x - 18 = 61 × 5}}}

{\bold{\sf\pink{➯ 19x - 18 = 305}}}

{\bold{\sf\pink{➯ 19x = 305 + 18}}}

{\bold{\sf\pink{➯ 19x = 323}}}

{\bold{\sf\pink{➯ x = 323/19}}}

{\bold{\sf\pink{➯ x = 17}}}

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Now, Putting value of x in eq (1),

{\bold{\sf\purple{➯ y = (3 × 17 - 6)/5}}}

{\bold{\sf\purple{➯ y = (51 - 6)/5}}}

{\bold{\sf\purple{➯ y = 45/5}}}

{\bold{\sf\orange{➯ y = 9}}}

∴ Hence, The length and breadth of rectangle is 17 units and 9 units respectively.

Answered by Anonymous
1

Answer:

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