The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units. If we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units. Find the dimensions of the rectangle.
Answers
Let assume that,
➢ Length of a rectangle be x units.
➢ Breadth of rectangle be y units.
➢ So, Area of rectangle = xy
According to first condition
The area of a rectangle gets reduced by 9 square units, if its length is reduced by 5 units and breadth is increased by 3 units.
Thus,
➢ Length of a rectangle = x - 5 units.
➢ Breadth of rectangle = y + 3 units.
So, Area of rectangle = (x - 5)(y + 3) square units
Also, Area of rectangle = xy - 9 square units
Thus, we have
According to second condition
If we increase the length by 3 units and the breadth by 2 units, the area increases by 67 square units.
So,
➢ Length of a rectangle = x + 3 units.
➢ Breadth of rectangle = y + 2 units.
So, Area of rectangle = (x + 3)(y + 2) square units
Also, Area of rectangle = xy + 67 square units
Thus, we have
On multiply equation (1) by 2 and equation (2) by 3, we get
and
On Subtracting equation (3) from equation (4), we get
On substituting the value of y in equation (1), we get
Hence,
Length of a rectangle = 19 units.
Breadth of rectangle = 17 units.