Question

The area of a rectangle is 100cmsquare and its length is 25cm.Find its width and perimater

Answer 1

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Area of rectangle = length × breadth.
Perimeter of rectangle = 2(length+breadth)
Given,
Area=100 cm sq.
Length =25 cm

Area=l×b
100=25×b
100/25=b
So, breadth=4 cm

Perimeter =2(l+b)
=2(25+4)
=2×29
=58 cm.

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Answer 2

Hello mate
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GIVEN,

$area = 100 {cm}^{2}$
$length = 25cm$

$area = l \times b$

$100 {cm}^{2} = 25cm \times b$

$\frac{100 {cm}^{2} }{25cm} = b$

$b = 4cm.$

$perimeter = 2(l + b)$

$perimeter = 2(25cm + 4cm)$

$perimeter = 2 \times 29cm$

$perimeter = 58cm.$

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