Question

The area of a rectangle is 102sqcm if it's length is 17cm what is it's perimeter

Answer 1

Hey there!!
let b be the breadth 

Area of rectangle = 102 
lb. = 102 
b = 102/17 
b = 6 

Perimeter of rectangle = 2 ( l+b) 

=> 2 ( 17 + 6)
=> 2×23
=> 46 cm

hope this helps u !!

Answer 2

Area=102 sqcm
length=17cm
Area=
$l \times b$
So, we have to find breadth
$b = \frac{area}{length}$
$b = \frac{102}{17}$
$b = 6$
Now, find the perimeter