Question

The area of a rectangle is 108 cm”, its breadth is 9 cm, find its perimeter.
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Answer 1

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• The area of a rectangle is 108 cm”, its breadth is 9 cm, find its perimeter.

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perimeter of RECTANGLE - 42 cm

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breath given = 9cm

$l \times b \: = \: 108 \\ l \: \times \: 9 = 108 \\ l = \frac{108}{9} \\ l = 12 \: cm$

$perimeter \: of \: rectangle \: = 2(l + b)$

$= 2(12 + 9) = 2 \times 21 = 42 \: cm$

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Answer 2

Answer:

perimeter of rectangle = 42cm

Explanation:

area = 108cm^2

breadth = 9cm

Area of rectangle = (l × b)

=》108 =(l × 9)

=》108/9= l

=》 l = 12

length of the rectangle = 12

perimeter of rectangle = 2 (l+b)

= 2 (12+9)

= 2 × 21

= 42cm

Therefore,perimeter of rectangle =42cm