Math, asked by shyamjeepal51, 7 hours ago

the area of a rectangle is 12.25sqcm greater than the area of a square of side7cm. if the breadth of tha rectangle is5cm. find its length.​

Answers

Answered by Anonymous
71

Answer:

Given :-

  • The area of a rectangle is 12.25 sqcm greater than the area of a square of side 7 cm.
  • Breadth of a rectangle is 5 cm.

To Find :-

  • What is the length of a rectangle.

Formula Used :-

\clubsuit Area of Square Formula :

\mapsto \sf\boxed{\bold{\pink{Area_{(Square)} =\: (Side)^2}}}\\

\clubsuit Area of Rectangle Formula :

\mapsto \sf\boxed{\bold{\pink{Area_{(Rectangle)} =\: Length \times Breadth}}}\\

Solution :-

First, we have to find the area of square :

Given :

  • Side = 7 cm

\implies \sf Area_{(Square)} =\: (7\: cm)^2

\implies \sf Area_{(Square)} =\: 7\: cm \times 7\: cm

\implies \sf \bold{\purple{Area_{(Square)} =\: 49\: cm^2}}

Now, we have to find area of rectangle :

\mapsto The area of a rectangle is 12.25 cm² greater than the area of a square :

\implies \sf Area_{(Rectangle)} =\: 49 + 12.25

\implies \sf Area_{(Rectangle)} =\: 49 + \dfrac{1225}{100}

\implies \sf Area_{(Rectangle)} =\: \dfrac{4900 + 1225}{100}

\implies \sf Area_{(Rectangle)} =\: \dfrac{6125}{100}

\implies \sf\bold{\purple{Area_{(Rectangle)} =\: 61.25\: cm^2}}

Now, we have to find the length of a rectangle :

Let,

\mapsto Length of Rectangle = x cm

Given :

  • Area of Rectangle = 61.25 cm²
  • Breadth of Rectangle = 5 cm

According to the question by using the formula we get,

\longrightarrow \sf x \times 5 =\: 61.25

\longrightarrow \sf 5x =\: 61.25

\longrightarrow \sf x =\: \dfrac{\dfrac{6125}{100}}{5}

\longrightarrow \sf x =\: \dfrac{6125}{100} \times \dfrac{1}{5}

\longrightarrow \sf x =\: \dfrac{6125}{500}

\longrightarrow \sf\bold{\red{x =\: 12.25\: cm}}

\therefore The length of a rectangle is 12.25 cm .

Answered by Saby123
64

Solution -

The area of a rectangle is 12.25 cm² greater than the area of a square of side 7 cm .

• The breadth of the rectangle is 5 cm .

We need to find the length of this rectangle .

To start , let us assign the length of the rectangle a variable , x .

Area of the rectangle becomes -

> Length × Breadth

> 5x cm ² .

The square has a sidelength of 7 cm .

Area of the square - 49 cm²

As per the question

5x = 49 + 12.25

> 5x = 60.25

> x = 12. 05 cm .

Answer - The length of the mentioned rectangle is 12.05 cm .

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 \setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 5 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 12.05 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

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