The area of a rectangle is 191 and 1/6 m square if the length is 15 and 1/2 m square the perimeter of the rectangle is
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◘ Given ◘
- The area of a rectangle, A = 191(1/6) m²
- Length of the rectangle, l = 15(1/2) m
◘ To Find ◘
The perimeter of the rectangle.
◘ Solution ◘
We know,
♣ Area of a rectangle = Length × Breadth
⇒ 191(1/6) = 15(1/2) × b
⇒ (191 × 6 + 1)/6 = (15 × 2 + 1)/2 × b
⇒ 1147/6 = 31/2 × b
⇒ 1147/6 ÷ 31/2 = b
⇒ b = 1147/6 × 2/31
⇒ b = (1147 × 2)/(6 × 31)
⇒ b = 2294/186
⇒ b = 12(1/3) m
_________________
We also know that,
♣ Perimeter of a rectangle, P = 2(l + b)
Substituting the values :-
P = 2[ 15(1/2) + 12(1/3) ]
⇒ P = 2(167/6)
⇒ P = 167/3
⇒ P = 55(2/3) m
Therefore, the perimeter of the rectangle is 55(2/3) m.
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