Question

The area of a rectangle is 192 sq cm and its perimeter is 56 cm . Find the dimensions of the rectangle .

Answer 1

area=192
let length be x
breadth be 192/x

according to question
2(l+b)=56
2(x+192/x)=56
2(x^2+192/x)=56
2x^2+384=56x
2x^2-56x+384
x^2-28x+192
x^2-16x-12x+192
x(x-16)-12(x-16)
(x-16)(x-12)
x=12 or 16
x=16
length is 16
breadth is 12
(because if x is 12 then breadth will be 16 and in a rectangle breadth cannot be bigger than length)

Answer 2

Step-by-step explanation:

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