Question

the area of a rectangle is 208sq. cm . the length is 16 cm . what is the breadth?

Answer 1

Answer:

• The breadth of the rectangle is 13 cm.

Step-by-step explanation:

Here, area and the length is given we need to find the breadth of the rectangle.

We know that,

Area of a rectangle = $l × b$

We have,

➙ $A$ (Area) = 208cm²

➙ $l$ (Length) = 16cm.

➙ $b$ (Breadth) = ?

From the given values :

→ $A = l × b$

→ 208 = 16 × $b$

→ 208/16 = $b$

→ $b$ = 13cm.

$\therefore$ The breadth of the rectangle is 13cm

Things to note :

• Calculation must be in same units
• The area of the figure will be measured in (unit)² if it's a 2 dimensional figure [rectangle]

Answer 2

$\LARGE\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

★Area of the rectangle = 208 ${cm}^2$

★Length of the rectangle = 16 cm .

$\underline \mathbb{TO \: FIND:-}$

Breadth of the rectangle .

$\underline \mathbb{FORMULA:-}$

Area =( Length × Breadth ) ${unit}^2$

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

$Area =( Length × Breadth ) {(unit)}^{2} \\ \\ \implies \: 208 = Length × 16 \\ \\ \implies \:Length = \cancel{\frac{208}{16}} \\ \\ \implies \:Length =13 \: cm \:$

$\underline \mathbb{ANSWER:-}$

$\implies \boxed{\:Length =13 \: cm \: }$

$\underline \mathbb{EXTRA\: INFORMATION:-}$

★$Perimeter \: \: of \: rectangle = 2(length + breadth)\:unit$

★$Diagonal \: of \: a \: rectangle \: = \sqrt{ {l }^{2} + {b}^{2} \ } \:unit$