Question

The area of a rectangle is 21 cm², if one side exceeds the other by 4 cm ,find the dimensions of the rectangle.​

Answer 1

Answer:

Given: Area of given rectangle = 21 square cm

Given: Area of given rectangle = 21 square cmSolution:

Given: Area of given rectangle = 21 square cmSolution:Let Length of one side of given rectangle = x cm; then

Formula for Area of rectangle = L X W

Formula for Area of rectangle = L X WPut values in formula , we have

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0=> x(x + 7) -3(x + 7) = 0

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0=> x(x + 7) -3(x + 7) = 0=> (x -3) (x + 7) = 0

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0=> x(x + 7) -3(x + 7) = 0=> (x -3) (x + 7) = 0=> x -3 = 0 or x + 7 = 0

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0=> x(x + 7) -3(x + 7) = 0=> (x -3) (x + 7) = 0=> x -3 = 0 or x + 7 = 0=> x = 3 or x = - 7

Formula for Area of rectangle = L X WPut values in formula , we havex . ( x + 4) = 21=> x^2 + 4x = 21=> x^2 + 4x - 21 = 0=> x^2 + 7x - 3x - 21 = 0=> x(x + 7) -3(x + 7) = 0=> (x -3) (x + 7) = 0=> x -3 = 0 or x + 7 = 0=> x = 3 or x = - 7Length always have positive value.