Question

The area of a rectangle is 259 cm' and its length is 18.5 cm. Find (i) its breadth (ii) its perimeter

STEP BY STEP NEEDED!!!​

Answer 1

$\text{ Given : The area of a rectangle is 259 cm} \frak{^{2}} \\ \text{and its length is 18.5 cm.} \\ \qquad \quad \text{ Find (i) its breadth (ii) its perimeter}$

$\text{Solution : According to the question here} \\ \text{we are given that the area of rectangle is 259 cm}^{2} \\ \text{ and the length given is 18.5 cm.} \\ \\ </p><p> \text{Need To Find : (I) Breadth and (II) Perimeter}$

$\rm{Finding \: (I) : } \\ </p><p> \qquad \text{For finding breadth we need to use the formula : } \\ \\ \odot \: \frak{Area_{(Rectangle)} = length \times breadth} \\ \\ \dashrightarrow \frak{259 = 18.5 \times breadth} \\ \\ \dashrightarrow \frak{ \frac{259}{18.5} = breadth} \\ \\\star \quad \underline{ \boxed{\frak{ \red{breadth = 14 \: cm}}}}$

$\text{ Finding (II) : } \\ </p><p> \qquad \text{To find perimeter we need to use the formula for getting it } \\ \\ \odot \: \frak{{\sf P}erimeter_{(Rectangle)} = 2(Length + Breadth)} \\ \\ \frak{ \hookrightarrow {\sf P}erimeter_{(Rectangle)} = 2(18.5 + 14)} \\ \\ \frak{ \hookrightarrow {\sf P}erimeter_{(Rectangle)} = 2(22.5)} \\ \\ \star \quad \underline{ \boxed{\frak{ \green{{\sf P}erimeter_{(Rectangle)} = 46 \: cm}}}}$