Question

the area of a rectangle is 259cm2 and its length is 18.5cm. find its breadth and its perimeter

Answer 1

Answer:

Breath is 14 cm and Perimeter is 65 cm

Step-by-step explanation:

By the way this is a genius question huh

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

the area of a rectangle is 259cm2 and its length is 18.5cm. find its breadth and its perimeter.

$\huge {\boxed {\mathbb {ANSWER}}}$

${\boxed {\mathbb {GIVEN}}}$

• $Area \:of \:rectangle (A) =259{cm}^{2}$
• $Length\: of \:the\: rectangle(l) =18.5cm$

${\boxed {\mathbb {TO\:PROVE}}}$

• $Breadth of the rectangle (b)$
• $Perimeter of the rectangle(P)$

${\boxed {\mathbb {SOLUTION}}}$

${\boxed {A=l\times b}}$

• $A=Area\: of\: the\: rectangle$
• $l =Length\: of\: the\: rectangle$
• $b=breadth\: of\: the\: rectangle$

$Substitute\: the\: values$

$\implies 259=18.5\times b$

$\implies b=\frac{259}{18.5}$

$\implies{\boxed {\boxed {b=14cm}}}$

_________________________________________

${\boxed {P=2\times (l+b)}}$

• $P= Perimeter\: of \:the\: rectangle$
• $l=length\: of\: the\: rectangle$
• $b=breadth\: of \:the\: rectangle$

$Substitute\: the\: values$

$\implies P=2\times (18.5+14)$

$\implies P=2\times (32.5)$

$\implies {\boxed {\boxed {P=65cm}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

_________________________________________

$\huge {\boxed {\mathbb {EXTRA\INFORMATION}}}$

$Formulas$

$A=l\times b$

$P=2\times (l+b)$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$