Question

The area of a rectangle is 300 CM spquare and its length ratio breadth is equal to 4 ratio 3 find its perimeter and the length of its diagonal

Answer 1

Step-by-step explanation:

Given that area of rectangle=300cm square

ratio of length and breadth =4:3

let the dimensions of rectangle be 4x and 3x

we know that area of rectangle is l*b

where l is length and b is breadth

area= 4x *3x = 300 CM square

or, 12x square= 300 CM square

or, x square=300/12cm square

or, xsquare=25

or, x= 5

putting value of x in dimensions of rectangle we get

length = 4x=4*5=20cm

breadth=3x=3*5=15cm

since perimeter = 2(length+breadth)

=2(20+15)

=2*35

=70 cm

Diagonal formula=given below

=under root length square + b square

$\sqrt{(20) {}^{2} + (15) {}^{2} }$

=

$\sqrt{400 + 225}$

$\sqrt{625}$

=25 answer