Question

the area of a rectangle is 32/3 sq.cm and the length is 4/9 cm. find the width of the rectangle.​

Answer 1

Answer:

24

Step-by-step explanation:

area of rectangle = length x width

32/3 = 4/9 x width

width = 32x9/3×4

= 24

$\huge{ son \: prodigal}$

Answer 2

$\huge \fcolorbox{red}{green}{ \bf \blue {24 \: cm}}$

Step-by-step explanation:

QUESTION :-

The area of a rectangle is 32/3 cm² and the length is 4/9 cm. Find the width of the rectangle.

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SOLUTION :-

We know that,

Area of rectangle = length × width

=> width = Area ÷ Length

$= \bf \frac{32}{3} \div \frac{4}{9} cm \\ \\ = \bf \frac{ \cancel {32}^{8} }{ \cancel{3}} \times \frac{ \cancel {9}^{3} }{ \cancel{4}}cm \\ \\ = \bf8 \times 3cm \\ \\ = \bf \red{24cm}$

So,

the width of rectangle = 24 cm.

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hope it helps.

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