The area of a rectangle is 32m²,and width of this triangle is two times its length.What is the perimeter of this triangle.WITH EXPLANATION.
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Step-by-step explanation:
let the length be x
breadth be 2x
area = x ×2x
2x^2
but , area = 32m^2 (given )
2x ^2= 32 m^2
x^2 = 32m ^2/2
x^2 = 16m
x= route under 16
x= 4
hence, length =4
breadth =16
perimeter = 2 (4+16)
2 (20)
40
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