the area of a rectangle is 40 cm²and perimeter is 28 cm.what are its length and breadth
Answers
Answer :—
length : 10 cm
breadth : 4 cm
Solution :—
Given :—
Area : 40 cm²
Perimeter : 28 cm
We know that in a rectangle area is length times breadth and perimeter is twice the sum of length and breadth.
i.e
Area :- L×B
Perimeter :- 2(L+B)
So,
2(L+B) = 28 Perimeter Given
L+B = 14
L= 14-B
L×B = 40 Area Given
(14-B)×B = 40 putting L = 14-B
14B-B²-40 = 0
B²-14B+40 = 0
B²-10B-4B+40 = 0
B(B-10)-4(B-10) = 0
(B-4)(B-10) = 0
B = 4 cm , 10 cm
So, L = 10 cm , 4 cm
if u have to opt for one of these answer. GO for
B = 4 cm
L = 10 cm
as normally we take breadth to be the smaller side
Given :-
- Area of Rectangle = 40 cm²
- Perimeter of rectangle = 28 cm .
To find :-
Length and Breadth of the rectangle .
Formula used :-
- Area of Rectangle = Length × Breadth .
- Perimeter of rectangle = 2( Length × Breadth )
Solution :-
- Let Length of rectangle = x cm .
- also, Breadth of rectangle = y cm .
Therefore, Area of Rectangle = x × y cm²
And,
Perimeter of rectangle = 2( x + y ) .
As we have Area of Rectangle = 40 cm²
Therefore,
x × y = 40 ............eq.(1)
also,
2( x + y ) = 28
divide both side by 2 we get :-
x + y = 14 ...........eq.(2)
From eq.(1)
x × y = 40
x = 40/y
Put the value of x = 40/y in eq.(2) we get :-
40 + y² = 14y
y² – 14y +40 = 0
Splitting the middle term .
y² – 10y – 4y + 40 = 0
y ( y – 10 ) – 4 ( y - 10 ) = 0
( y - 10 ) ( y - 4) = 0
y - 10 = 0
y = 10
y - 4 = 0
y = 4
Put the value of y = 10 in eq.(2)
x + y = 14
x + 10 = 14
x = 4
Also Put the value of y = 4 in eq.(2)
x + y = 14
x + 4 = 14
x = 10 .
Therefore, When Breadth of rectangle is 10 cm then Length will be 4 cm .
if Breadth of rectangle is 4 cm then Length will be 10 cm .
Some knowledge about Rectangle :-
- Rectangle have to diagonal . both are equal to each other .
- Rectangle have 4 angles all are of 90° .
- Opposite sides of Rectangle are equal and parallel .
- Rectangle can also called parallelogram.